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Study Notes/Grade 9 Math/Quadratic Functions
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Lesson 2 • 40 min read

Quadratic Functions

1What is a Quadratic Function?

A quadratic function is any function that can be written in the form f(x) = ax² + bx + c, where a ≠ 0. The graph of a quadratic function is always a parabola.

Examples of Quadratic Functions:

f(x) = x²

Simplest form

f(x) = 2x² - 3x + 1

Standard form

f(x) = -(x - 2)² + 5

Vertex form

Key Characteristics:

  • • Highest power of x is 2 (degree 2)
  • • Graph is always a U-shaped curve (parabola)
  • • Has exactly one vertex (turning point)
  • • Has an axis of symmetry through the vertex

2Standard & Vertex Forms

Standard Form

f(x) = ax² + bx + c

Best for:

  • • Finding y-intercept (c)
  • • Using quadratic formula
  • • Identifying a, b, c coefficients

Vertex Form

f(x) = a(x - h)² + k

Best for:

  • • Finding vertex: (h, k)
  • • Graphing quickly
  • • Finding axis of symmetry: x = h

Converting Between Forms

Example: Convert f(x) = (x - 3)² + 2 to standard form

f(x) = (x - 3)² + 2

f(x) = (x² - 6x + 9) + 2 ← Expand (x-3)²

f(x) = x² - 6x + 11

3Properties of Parabolas

If a > 0 (Positive)

Opens UPWARD

  • • Vertex is the MINIMUM point
  • • Function decreases then increases
  • • Smiling parabola

If a < 0 (Negative)

Opens DOWNWARD

  • • Vertex is the MAXIMUM point
  • • Function increases then decreases
  • • Frowning parabola

Effect of |a| (Absolute Value)

|a| > 1: Narrower parabola

Example: f(x) = 3x² is narrower than f(x) = x²

|a| < 1: Wider parabola

Example: f(x) = 0.5x² is wider than f(x) = x²

Key Features

Vertex: The highest or lowest point (h, k)

Axis of Symmetry: Vertical line x = h through the vertex

Y-intercept: Where the parabola crosses y-axis (0, c)

X-intercepts (Roots): Where the parabola crosses x-axis (if any)

4Finding the Vertex

From Standard Form (ax² + bx + c)

h = -b / 2a

k = f(h)

Vertex = (h, k)

Example: Find vertex of f(x) = x² - 4x + 3

a = 1, b = -4, c = 3

h = -b/2a = -(-4)/2(1) = 4/2 = 2

k = f(2) = (2)² - 4(2) + 3 = 4 - 8 + 3 = -1

Vertex: (2, -1)

Example 2: Find vertex of f(x) = -2x² + 8x - 5

a = -2, b = 8, c = -5

h = -8/2(-2) = -8/(-4) = 2

k = -2(2)² + 8(2) - 5 = -8 + 16 - 5 = 3

Vertex: (2, 3)

Since a < 0, this is a maximum

From Vertex Form (a(x - h)² + k)

The vertex is simply (h, k) - just read it directly!

f(x) = 3(x - 2)² + 5 → Vertex: (2, 5)

f(x) = -(x + 1)² - 3 → Vertex: (-1, -3)

Note: (x + 1) = (x - (-1)), so h = -1

5Graphing Quadratic Functions

Steps to Graph

  1. Determine if parabola opens up (a> 0) or down (a< 0)
  2. Find and plot the vertex (h, k)
  3. Draw the axis of symmetry: x = h
  4. Find and plot the y-intercept (0, c)
  5. Use symmetry to plot the mirror point
  6. Find x-intercepts (if they exist) by solving f(x) = 0
  7. Connect points with a smooth U-shaped curve

Example: Graph f(x) = x² - 2x - 3

1. a = 1 > 0, so opens upward

2. Vertex: h = -(-2)/2(1) = 1, k = 1 - 2 - 3 = -4 → (1, -4)

3. Axis of symmetry: x = 1

4. Y-intercept: (0, -3)

5. Mirror of (0, -3) across x=1 is (2, -3)

6. X-intercepts: x² - 2x - 3 = 0 → (x-3)(x+1) = 0 → (-1, 0) and (3, 0)

Quick Graphing Tips

• Always plot at least 5 points for accuracy

• Use symmetry! Points equidistant from axis have same y-value

• The vertex is always on the axis of symmetry

• Check your graph: parabola should be symmetric